Table of Contents
Overview
The objective is to find the print n number of rows of Pascal’s triangle. The number n is given as an input to the program
Example 1
Input: numRows = 4
Output: [[1],[1,1],[1,2,1],[1,3,3,1]]
Example 2
Input: numRows = 5
Output: [[1],[1,1],[1,2,1],[1,3,3,1],[1,4,6,4,1]]
Refer to this link to know more about Pascal’s Triangle here – https://en.wikipedia.org/wiki/Pascal%27s_triangle
The idea is to use dynamic programming here.
Program
Below is the program for the same
package main
import "fmt"
func generate(numRows int) [][]int {
firstRow := []int{1}
if numRows == 1 {
return [][]int{firstRow}
}
secondRow := []int{1, 1}
if numRows == 2 {
return [][]int{firstRow, secondRow}
}
output := [][]int{firstRow, secondRow}
for i := 2; i < numRows; i++ {
temp := make([]int, i+1)
lastRow := output[i-1]
temp[0] = 1
temp[i] = 1
for j := 1; j < i; j++ {
temp[j] = lastRow[j-1] + lastRow[j]
}
output = append(output, temp)
}
return output
}
func main() {
output := generate(4)
fmt.Println(output)
output = generate(5)
fmt.Println(output)
}
Output:
[1] [1 1] [1 2 1] [1 3 3 1]]
[[1] [1 1] [1 2 1] [1 3 3 1] [1 4 6 4 1]]
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