Overview
An array is given. The objective is to find if there exists any number for which it’s double also exists.
Example 1
Input: [8,5,4,3]
Output: true
Explanation: 4 and 8
Example 2
Input: [1,3,7,9]
Output: false
Explanation: There exists no number for which its double exist
The idea is to use a map here. For every element, we will check and return true if
- If its double exists in the map
- If the number is even then if its half exists in the map
Program
Below is the program for the same
package main
import "fmt"
func checkIfExist(arr []int) bool {
numMap := make(map[int]bool)
for i := 0; i < len(arr); i++ {
if numMap[arr[i]*2] {
return true
}
if arr[i]%2 == 0 && numMap[arr[i]/2] {
return true
}
numMap[arr[i]] = true
}
return false
}
func main() {
output := checkIfExist([]int{8, 5, 4, 3})
fmt.Println(output)
output = checkIfExist([]int{1, 3, 7, 9})
fmt.Println(output)
}
Output:
true
false
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Also, check out our system design tutorial series here - System Design Tutorial Series