Introduction

A binary search tree abbreviated as BST is a binary tree. For each node in a Binary Search Tree

• Value of each node in the left  subtree is less than the current node value

• Value of each node in the right subtree is greater than the current node value

• Both left and right subtree are themselves Binary Search Tree

Full Working Code

insertRec() function inserts into the bst in an iterative manner

package main

import "fmt"

type bstnode struct {
    value int
    left  *bstnode
    right *bstnode
}

type bst struct {
    root *bstnode
}

func initList() *bst {
    return &bst{}
}

func (b *bst) reset() {
    b.root = nil
}

func (b *bst) insert(value int) {
    b.insertRec(b.root, value)
}

func (b *bst) insertRec(node *bstnode, value int) {
    if b.root == nil {
        b.root = &bstnode{
            value: value,
        }
    }
    if node == nil {
        return
    }
    //Find the terminalNode where to insert the new node
    var terminalNode *bstnode
    for node != nil {
        terminalNode = node
        if value <= node.value {
            node = node.left
        } else {
            node = node.right
        }
    }
    if value <= terminalNode.value {
        terminalNode.left = &bstnode{value: value}
    } else {
        terminalNode.right = &bstnode{value: value}
    }
    return
}

func (b *bst) find(value int) error {
    node := b.findRec(b.root, value)
    if node == nil {
        return fmt.Errorf("Value: %d not found in tree", value)
    }
    return nil
}

func (b *bst) findRec(node *bstnode, value int) *bstnode {
    if node == nil {
        return nil
    }
    if node.value == value {
        return b.root
    }
    if value < node.value {
        return b.findRec(node.left, value)
    }
    return b.findRec(node.right, value)
}

func (b *bst) inorder() {
    b.inorderRec(b.root)
}

func (b *bst) inorderRec(node *bstnode) {
    if node != nil {
        b.inorderRec(node.left)
        fmt.Println(node.value)
        b.inorderRec(node.right)
    }
}

func main() {
    bst := &bst{}
    eg := []int{2, 5, 7, -1, -1, 5, 5}
    for _, val := range eg {
        bst.insert(val)
    }
    fmt.Println("Printing Inorder")
    bst.inorder()
    bst.reset()
    eg = []int{4, 5, 7, 6, -1, 99, 5}
    for _, val := range eg {
        bst.insert(val)
    }
    fmt.Println("Printing Inorder")
    bst.inorder()
    err := bst.find(2)
    if err != nil {
        fmt.Printf("Value %d Not Found\n", 2)
    } else {
        fmt.Printf("Value %d Found\n", 2)
    }
    err = bst.find(6)
    if err != nil {
        fmt.Printf("Value %d Not Found\n", 6)
    } else {
        fmt.Printf("Value %d Found\n", 6)
    }
    err = bst.find(5)
    if err != nil {
        fmt.Printf("Value %d Not Found\n", 5)
    } else {
        fmt.Printf("Value %d Found\n", 5)
    }
    err = bst.find(1)
    if err != nil {
        fmt.Printf("Value %d Not Found\n", 1)
    } else {
        fmt.Printf("Value %d Found\n", 1)
    }
}

Output:

Printing Inorder
-1
-1
2
5
5
5
7
Printing Inorder
-1
4
5
5
6
7
99
Value 2 Not Found
Value 6 Found
Value 5 Found
Value 1 Not Found