Overview
Given an integer array and a target number, the objective is to find the number of combinations from the integer array that sum to the target number.
Each of the elements in the array could be used any number of times in the same combination
Examples
Input: [3,4,10,11]
Target: 10
Output: [[3,3,4],[10]]
Program
Here is the program for the same.
package main
import "fmt"
func combinationSum(candidates []int, target int) [][]int {
lengthCandidates := len(candidates)
current_sum_array := make([]int, 0)
output := make([][]int, 0)
combinationSumUtil(candidates, lengthCandidates, 0, 0, 0, target, current_sum_array, &output)
return output
}
func combinationSumUtil(candidates []int, lengthCandidates, index, current_sum_index, current_sum, target int, current_sum_array []int, output *[][]int) {
if index >= lengthCandidates {
return
}
if current_sum > target {
return
}
if current_sum == target {
var o []int
for i := 0; i < current_sum_index; i++ {
o = append(o, current_sum_array[i])
}
*output = append(*output, o)
return
}
//Exclude
combinationSumUtil(candidates, lengthCandidates, index+1, current_sum_index, current_sum, target, current_sum_array, output)
//Include
current_sum_array = append(current_sum_array, candidates[index])
combinationSumUtil(candidates, lengthCandidates, index, current_sum_index+1, current_sum+candidates[index], target, current_sum_array, output)
}
func main() {
output := combinationSum([]int{3, 4, 10, 11}, 10)
fmt.Println(output)
}
Output
[[10] [3 3 4]]
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