Table of Contents
Overview
Question Mark is the optional operator in regex. This means that it optionally matches the preceding character before the question mark
Eg.
abcd?
This will match both “abc” and “abcd”.
Program
Let’s see an example for the same.
package main
import (
"fmt"
"regexp"
)
func main() {
sampleRegexp := regexp.MustCompile("abcd?")
match := sampleRegexp.Match([]byte("abc"))
fmt.Printf("For abc: %t\n", match)
match = sampleRegexp.Match([]byte("abcd"))
fmt.Printf("For abcd: %t\n", match)
}
Output
For abc: true
For abcd: true
Several characters can also be made optional by closing them with parentheses and then putting the question mark behind them. Eg
abc(de)?
package main
import (
"fmt"
"regexp"
)
func main() {
sampleRegexp := regexp.MustCompile("abc(de)?")
match := sampleRegexp.Match([]byte("abc"))
fmt.Printf("For abc: %t\n", match)
match = sampleRegexp.Match([]byte("abcde"))
fmt.Printf("For abcde: %t\n", match)
match = sampleRegexp.Match([]byte("abcd"))
fmt.Printf("For abcd: %t\n", match)
}
Output
For abc: true
For abcde: true
For abcd: true
It matches “abc” and “abcde”.
It also matched “abcd”. You must be wondering why it matched “abcd”.
If the given string or text contains the regex as a substring then also it gives a match. That is why it gave a match as “abcd” contains “abc” as a substring which is a match for regex. If we want to do full string matches then we need to use the anchor characters at the start and end of the regex. Caret anchor character will be used at the start and Dollar anchor character will be used at the end.
Let’s see an example for the same.
package main
import (
"fmt"
"regexp"
)
func main() {
sampleRegexp := regexp.MustCompile("^abc(de)?$")
match := sampleRegexp.Match([]byte("abc"))
fmt.Printf("For abc: %t\n", match)
match = sampleRegexp.Match([]byte("abcde"))
fmt.Printf("For abcde: %t\n", match)
match = sampleRegexp.Match([]byte("abcd"))
fmt.Printf("For abcd: %t\n", match)
}
Output
For abc: true
For abcde: true
For abcd: false
Question Mark Operator is non-lazy
Question Mark Operator is non-lazy or greedy. This means that it will match the optional pattern first.
In the regular expression world, non-lazy(or sometimes also called greedy) means trying to match as much as possible. While lazy(or sometimes also called non-greedy) means matching only as much as needed.
For example for the given regex
https?
If you try to match the below input string
Better is https
Then there are two options
- Match http
- Match https
Then it will always match https and never http. The reason is that it is non-lazy. Even when it matches http it doesn’t stop and tries to match the optional character as well. If the optional character matches then it returns https otherwise it returns http.
Let’s see an example for the same
package main
import (
"fmt"
"regexp"
)
func main() {
sampleRegexp := regexp.MustCompile("https?")
match := sampleRegexp.Find([]byte("Better is https"))
fmt.Printf("Match: %s\n", match)
}
Output
Match: https
In the above program, we have used the Find function which returns the actual substring that matched with a regex. As you can notice in the output it matched “https” and not “http” because the question mark operator is non-lazy
About the double question mark operator
It is lazy. As soon it finds the first match, it does not try to match further. So for the above text, it will always give result as “http” and never “https”.
Let’s see an example
package main
import (
"fmt"
"regexp"
)
func main() {
sampleRegexp := regexp.MustCompile("https??")
match := sampleRegexp.Find([]byte("Better is https"))
fmt.Printf("Match: %s\n", match)
}
Output
Match: http
Question Mark after quantifiers
The question mark ‘?’ after quantifiers is lazy or non-greedy. The quantifiers could be
- Plus ‘+’ – One or more
- Asterisk ‘*’ – Zero or more
See below example
package main
import (
"fmt"
"regexp"
)
func main() {
sampleRegexp := regexp.MustCompile("http(s+?)")
match := sampleRegexp.Find([]byte("Better is httpsss"))
fmt.Printf("Match: %s\n", match)
sampleRegexp = regexp.MustCompile("http(s*?)")
match = sampleRegexp.Find([]byte("Better is httpsss"))
fmt.Printf("Match: %s\n", match)
}
Output
Match: https
Match: http
In the above program, we have two cases
- Question mark after a plus operator
- Qusetion mark after asterisk operator
In both the case the input string is
Better is httpsss
In the first case, we used a question mark after the plus operator in the regex
"http(s+?)"
It gives below match as “https” instead of “httpsss” as question mark when used after the Plus operator is non-greedy
In the second case, we used a question mark after the asterisk sign in the regex
"http(s*?)"
It gives match as “http” instead of “httpsss” as the question mark when used after the Asterisk operator is non-greedy
Let’s see another example
package main
import (
"fmt"
"regexp"
)
func main() {
sampleRegexp := regexp.MustCompile("(a+?)(a*)")
match := sampleRegexp.FindStringSubmatch("aaaaaaa")
fmt.Printf("Match: %s Length: %d\n", match, len(match))
sampleRegexp = regexp.MustCompile("(a*?)(a*)")
match = sampleRegexp.FindStringSubmatch("aaaaaaa")
fmt.Printf("Match: %s Length: %d\n", match, len(match))
}
Output
Match: [aaaaaaa a aaaaaa] Length: 3
Match: [aaaaaaa aaaaaaa] Length: 3
In the above program, again we have two cases
- A question mark after a plus operator
- A question mark after asterisk operator
In the first case, we have regex with two capture groups
(a+?)(a*)
The first capture group gives a single match of ‘a’ while the second capture group gives the rest. This show question mark operator used after the Plus operator is non-greedy or lazy
In the second case, we have regex again with two capture groups
(a*?)(a*)
The first capture group gives a zero match of ‘a’ while the second capture group gives the rest. This show question mark operator used after Asterisk operator is non-greedy or lazy
This is all about the question mark operator in Go. Hope you have liked this article. Please share feedback in the comments.
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